Quantity of Sand in cum = 1.54 / 7 × 2 (where 2 is the ratio of sand) = 0.44 cum Quantity of Sand in kg = 0.44 × 1450 (density of sand = 1450 to 1500 kg/m3) Quantity of Sand in cubic feet = 1.54 / 7 × 2 × 35.314 (1 cum = 35.314 cft)

Make a farma i.e. wooden box open from two sides (top and bottom) in multiples of 1.25 cubic feet. Measure your sand and aggregate in this farma and take your 50 kg cement bag as 1.25 cft.

14/04/2020· It is note that this is not standard size of truck value in foot is taken just for example for calculation of quantity of sand in cft. Volume of sand = l × b × h. Volume of sand = 15′ × 6′ × 5′ Volume of sand = 450 cubic feet. 450 cubic feet of sand quantity loaded in in one truck of medium size Ans. :- The value of sand quantity in truck in CFT is about 450.

03/08/2018· For Calculate in CFT (Cubic Feet) = 8 x 1.225 = 9.8 Cubic Feet CALCULATION FOR SAND QUANTITY Consider volume of concrete = 1m3 Dry Volume of Concrete = 1 x 1.54 = 1.54 m3

24/01/2018· Step-1: Calculate the Volumes of material required in 1 Cum concrete The dry volume of concrete mixture is always greater than the wet volume. The ratio of dry volume to the wet volume of concrete is 1.54. So 1.54 Cum of dry materials (cement, sand and aggregate) is required to produce 1 Cum of concrete

Dry Sand – 1540 to 1600 kg/m 3 Aggregate – 1560 to 1600 kg/m 3. Wet to Dry Conversion. Dry Volume = Wet Volume + 54% of wet volume Dry Volume = Wet Volume x 1.54. How to calculate quantity for 10 cubic meter concrete. We have been given Grade – M15 and we have to calculate the quantity of cement, sand and aggregate in cft, cum and kg.

16/08/2020· 1 cft sand weight in kg:-Dry loose Bulk density of Sand is about 1600 kg/cum, 1 cum sand weighs 1600 kgs, we know 1m3 = 35.32 cft, so 35.32 cft = 1600 kgs,1 cft sand weight = 1600/35.32 kgs = 45.3 kgs, so 1 cft of sand would weigh around 45 kgs.

01/09/2020· So you get sand density = 1650 / 35.32 = 46.71 Kg/cft No measure your sand volume at site in cft and multiply it with above density per cft. say you have 100 cft sand at site - so its total weight will be = 46.71 x 100 = 4671 Kg. You can use any size and shape box of known measurement for calculation of density.

06/07/2019· When you enter your measurements into the calculator, it works out the area and volume of the sand required using the below formulas: $$Area = Length \times Width$$ $$Volume = …

Step-1: Calculate Volume of Materials required Density of Cement = 1440 kg/cum (Approx) Volume of 1 Kg of Cement = 1/1440 = 0.000694 cum Volume of 01 bag (50 kg) of cement = 50 X 0.000694 = 0.035 cubic meter (cum)

1.54 of concrete X 4 ratio of aggregate divide 7 X 35.3147 = 31.07 cft ( we know that 1 cum is equal to 35.3147 cft ) Conclusion: For 1 cubic meter of concrete following quantities are required: cement = 7.77 cubic feet; sand = 15.54 cubic feet; Aggregate …

01/09/2020· So you get sand density = 1650 / 35.32 = 46.71 Kg/cft No measure your sand volume at site in cft and multiply it with above density per cft. say you have 100 cft sand at site - so its total weight will be = 46.71 x 100 = 4671 Kg. You can use any size and shape box of …

24/01/2018· Step-1: Calculate the Volumes of material required in 1 Cum concrete The dry volume of concrete mixture is always greater than the wet volume. The ratio of dry volume to the wet volume of concrete is 1.54. So 1.54 Cum of dry materials (cement, sand and …

Calculation For Sand: Formula, Sand = (Volume of dry concrete/a+b+c) × b = (1.54/a+b+c) × b = (1.54/1+2+4) × 2 = 0.44 cum.

When you enter your measurements into the calculator, it works out the area and volume of the sand required using the below formulas: $$Area = Length \times Width$$ $$Volume = Area \times Depth$$

Therefore we are multiplying the 1440 kg density of cement to calculate the cement quantity. Required amount Cement quantity = 63 Kg = 1.26 bags (50 Kg bag) Required amount of Sand = 0.306565 X 6/7 = 0.26277 Cubic metre (m3) Therefore, For 1 cum of brickwork, we need

Quantity of sand = 0.42 x 35.3147 = 14.832 CFT Weight of sand = volume x density, Density of Sand = 1650 kg/m^3 Weight of sand= 0.42 x 1650= 693 kg (0.693 tonnes) 3- …

The volume formula for a rectangular (or square) box in cubic feet is height (ft) x width (ft) x length (ft), as seen in the figure below: For example, to fill a box with a width of 3ft and a length of 6ft, to a depth of 1ft, you need to multiply 1ft x 3ft x 6ft = 18ft 3 (cubic feet) of sand.

For Beam, If we need to calculate the concrete volume, Volume = Length X Breadth X Width = 5 X 0.6 X 0.3 = 3.75 m3 For Column, If we need to calculate a concrete volume for the below Columns, Rectangular Column, Volume = Height X Breadth X Width = 5 X 0.6 X 0.3 = 0.9 m 3

1.54 of concrete X 4 ratio of aggregate divide 7 X 35.3147 = 31.07 cft ( we know that 1 cum is equal to 35.3147 cft ) Conclusion: For 1 cubic meter of concrete following quantities are required: cement = 7.77 cubic feet; sand = 15.54 cubic feet; Aggregate …

Cft>>> 137.5×40.77= 5606 Kg. Cum>>> 3.9×1440= 5606 kg. To convert into Bags divide by 50 (50 kg in one bag of cement) 5606/50 = 112 bags of cement. Or directly calculate cement bags from Volume: Volume of cement bag= 0.034cum or 1.226cft. Cft>>> 137.5÷1.226 = 112 Bags. Calculation of sand in Concrete: Quantity of Sand = (2÷7)×962.5 = 275 Cft. Sand = (2÷7)×27.25 = 7.78 Cu.m. Density of ...

Therefore we are multiplying the 1440 kg density of cement to calculate the cement quantity. Required amount Cement quantity = 63 Kg = 1.26 bags (50 Kg bag) Required amount of Sand = 0.306565 X 6/7 = 0.26277 Cubic metre (m3) Therefore, For 1 cum of brickwork, we need

08/08/2018· Now we find how many CFT (Cubic feet) Required As we know that 1m3 = 35.31 CFT = 0.124*35.31 = 4.37 CFT (Cubic Feet)

Quantity of sand = 0.42 x 35.3147 = 14.832 CFT Weight of sand = volume x density, Density of Sand = 1650 kg/m^3 Weight of sand= 0.42 x 1650= 693 kg (0.693 tonnes) 3- …

So care should be taken while calculating the amount of Cement, Sand and Aggregate required for 1 Cubic meter of Concrete. Method-1: DLBD method to determine material requirement for 1 Cum concrete The DLBD (Dry Loose Bulk Densities) method is an accurate method to calculate cement, sand and aggregate for a given nominal mix concrete.

The calculation process is as follows: Estimate the volume of sand needed, using geometrical formulas and plans or measurements. The approximate density of sand is 1600 kg/m 3 (100 lb/ft 3 ). Multiply the volume by the density (in the same units) to get the weight

1 cubic meter (m3) = 35.3146667 cubic feet (ft3) 1 cubic foot (ft3) = 0.0283168 cubic meters (m3)

Volume of Sand =1.5/5.5 x 1.55. Volume of Coarse Aggregate = 3/5.5 x 1.55. So the required Cement Volume – 0.282 m 3 or 8.14 Bags Sand Volume – 0.423 m 3. Coarse Aggregate – 0.845 m 3. Water Cement Ratio Calculation. From the IS Code standard, Assuming the water-cement ratio for M20 is 0.55.

We will calculate cement and sand for 100 m 2 plastering area in 1:6 ratio and thickness of 12 mm. Cement Mortar Required: Plastering thickness = 12 mm = 12/1000 = 0.012m . Volume of cement mortar required = ( Plastering Area x thickness ) = 100 m 2 x 0.012m = 1.2 m 3 (This is wet volume of cement mortar (after mixing water) but we need dry volume. To get dry volume consider 35% bulking of ...